February 28, 2020
If you choose the cross product of this very first issue’s vectors, then you will find a vector (0, 0, -.7072). Assuming you stick using the formula you gave, you will want to work with a 180-degree abbreviated variation of this vector whenever you have a magnitude for the cross-platform product, that the equation spits out. Take the product of the second problem’s vectors. You will not do anything, as this size is positive if you are still using the equation.